The cost, C. of producing coolers, x, is modeled by the equation C = 0.005x2 - 0.3x + 17. How many coolers are produced when the cost is $19. Round your answers to the nearest whole number

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66 coolers

Step-by-step explanation:

C = 0.005x² - 0.3x + 17

When C = $19

19 = 0.005x² - 0.3x + 17

19 - 17 = 0.005x² - 0.3x

2 = 0.005x² - 0.3x

0.005x² - 0.3x - 2 = 0

x = -b ± √b² - 4ac / 2a

= -(-0.3) ± √-0.3² - 4*0.005*-2 / 2*0.005

= 0.3 ± √ 0.09 - (-0.04) / 0.01

= 0.3 ± √ 0.09 + 0.04 / 0.01

= 0.3 ± √ 0.13 / 0.01

= 0.3/0.01 ± √0.13/0.01

= 30 ± 0.36/0.01

x = 30 ± 36

x = 30 + 36 or 30 - 36

x = 66 or -6

Number of coolers can not be negative

Therefore, number of coolers produced when the cost is $19

is 66 coolers

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2