The Suarez family paid $12.00 for 3 movie tickets. How much would they have paid for 9 tickets?

$36 (see below)

Step-by-step explanation:

First, you have to find how much they paid for one ticket.

If they paid $12 for 3, then they paid $4 for 1.

You could've also use a ratio:

$12         $x

=  

 3             1

Cross multiply:

$12 (1) = $3x

$12 = $3x

$4 = x

So $4 for 1 ticket.

To find the cost of 9 tickets, just multiply the price by the number of tickets, which is:

$4 (9) = $36

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.