Use Pascal's Triangle to help find the missing values. x^4-4x^b+6x^2-ax+1

a=

b=

The value of a = 4 , b = 3

Step-by-step explanation:

Given the equation,

x⁴ - 4 + 6x² - ax + 1

so, the coefficients are -      1     4      6     a     1

the Pascal's triangle is as follows :

                                         1

                              1                     2

                   1                   2                        1

         1                   3                   3                         1

 1                4                   6                      4                       1

So,

from Pascal's triangle ,

we can see that , after comparing with given equation , we get

Row n = 4

The coefficient be 1 4 6 4 1

∴ we get

a = 4

and

(x+y)⁴ = x⁴ + 4x³y + 6x²y² + 4xy³ + y⁴

Now, as given equation be x⁴ - 4 + 6x² - ax + 1

By comparing we get y = -1 and b = 3

So, we get

a = 4 , b = 3

could you reply to this with the question so i can ?

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles