how many footballs fields (with dimensions 300 ft by 160 ft) are needed to accommodate 50,000 students if each student has 4 square feet to stand?

The area of the polo field is 300 yd x 160 yd = 48000 yards

The football field is 160 feet wide. THere are 3 feet per yard, so

the football field is 160/3 = 53 and 1/3 yards wide.

So the area of the football field is 100 yards x 53 1/3 yards

                                            = 100 yards x 160/3 yd

                                            = 16000/3 square yards

                                            =  5333 and 1/3 square yards

Dividing these areas, then they will need 48000 / (5333 and 1/3)

                                                          48000 / (16000/3) =

                                                          48000 * 3 / 16000  <-- dividing fractions; KFC: keep, flip, change; (reciprocal)

                                                           3 * 3     < 48000 cancels 16000 3 times

                                                             9

i'm not sure i quite understand, could you provide more information?

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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