An electronic office product contains 5100 electronic components. Assume that the probability that each component operates without failure during the useful life of the product is 0.999, and assume that the components fail independently. Approximate the probability that 2 or more of the original 5100 components fail during the useful life of the product. Use normal approximation. Round your answer to 3 decimal places.

The probability that 2 or more of the original 5,100 components may fail during the useful life of the product is:

= 0.001

Step-by-step explanation:

Probability of operating without failure = 0.999

The probability of failed component = 0.001 (1 - 0.999)

The number of components of the electronic office product = 5,100

The number of components that may fail, given the above successful operation = 5.1 (0.001 * 5,100).

Therefore, the probability that 2 or more of the original 5,100 components may fail during the useful life of the product = 0.001

Probability of component failure is the likelihood that a component fails during the useful life of the product.  It is expressed as the number of likely failed components divided by the total number of components.  This result can be left in decimal form or expressed as a percentage.

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680