He data to the right represent the top speed (in kilometers per hour) of all the players (except goaltenders) in a certain soccer league. construct (a) a relative frequency distribution (b) a frequency histogram, and (c) a relative frequency histogram. what percentage of players had a top speed between 1818 and 21.921.9 km/h? what percentage of players had a top speed less than 13.913.9 km/h? speed (km/hr) number of players 10 dash 13.910–13.9 44 14 dash 17.914–17.9 77 18 dash 21.918–21.9 1414 22 dash 25.922–25.9 5959 26 dash 29.926–29.9 324324 30 dash 33.930–33.9 181181 (a) construct a relative frequency distribution. speed (km/hr) relative frequency 10 dash 13.910–13.9 nothing 14 dash 17.914–17.9 nothing 18 dash 21.918–21.9 nothing 22 dash 25.922–25.9 nothing 26 dash 29.926–29.9 nothing 30 dash 33.930–33.9 nothing (round to four decimal places as needed.)

answer: i oofed

step-by-step explanation:

oofed=wow

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116