Write your name on your response sheet. Explain your answers in as much detail as possible. Check your examples and results. You need to explain every step of your logic, development andcalculation. No credit will be given without the intermediate steps or the explanations. Please readall questions before you start your answers. Let
A= [1 2 2 2]
[2 5 5 7]
[3 6 6 6]

1. Find all possible solutions of the homogeneous system Ax = 0.
2. Find all possible solutions of Ax = 6, where

[3]
b = [7]
[9]

d

step-by-step explanation:

d

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

step-by-step explanation: