Find the positive zero of the function f(x)=x^(2)-5x-7 and round two decimal places

6.14

Step-by-step explanation:

Given the function f(x)=x^(2)-5x-7, when f(x) = 0

x^(2)-5x-7 = 0

Using the general formula

x = 5±√5²-4(-7)/21(1)

x= 5±√25+28/2

x = 5±√53/2

x = -5±7.28/2

x = 5+7.28/2 and 5-7.28/2

x = 12.28/2 and -2.28/2

x = 6.14 and -1.14

Hence the positive zero is 6.14

d 192

step-by-step explanation:

we find our area to find area we multiply thoses numbers to get our answer so our area is 192

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)