This probability distribution shows the typical grade distribution for a Geometry course with 35 students. HELLLPPP PLSSS

P(A, B or C) = 6/7 or 0.8571

Step-by-step explanation:

From the image, we have the frequency for each grade as;

Grade A = 5

Grade B = 10

Grade C = 15

Grade D = 3

Grade F = 2

We want to find the probability that a student earns a grade of A, B or C.

Total frequency for A, B & C = 5 + 10 + 15 = 30

There are a total of 35 students overall for the geometry course.

Thus;

P(A, B or C) = 30/35

P(A, B or C) = 6/7 or 0.8571

Step-by-step explanation:

Total frequency for A, B & C = 5 + 10 + 15 = 30

There are a total of 35 students overall for the geometry course.

P(A, B or C) = 30/35

P(A, B or C) = 6/7 or 0.8571

now we round to the hundredths place

0.8571 ⇒ 0.86

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100