The perpendicular bisectors of triangle RST intersect at K. Find KR

Step-by-step explanation:

Remark

The diagram is a mess of lines; you have to guess where that 12 belongs. Just to make the question a bit more interesting, I'm going to say the 12 belongs to the perpendicular.

If that's true you can find KT using Pythagorus. KT and RT are equal. (SSS)

So, let's go.

Givens

1/2 of ST = 1/2 32 = 16

12 is the leg of the small triangle KT and the third point where the perpenduclar line meets ST.

Solution

KT^2 = 16^2 + 12^2

KT^2 = 256 + 144

KT^2 = 400

KT = sqrt(400)

KT = 20

RK = KT because parts of a congruent triangle = parts of the other triangle containing the line (KT) that you are trying to find the length of.

step-by-step explanation:

b and c

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.