if y varies jointly as the square of x and the cube of z and inversely as the square root of w. When x = 2, z = 2, and w = 64, then y = 12. Find y when x = 1, z = 3, and w = 4.

40.5

Step-by-step explanation:

if y varies jointly as the square of x and the cube of z and inversely as the square root of w, this is expressed as;

y ∝ x²z³/√w

y = kx²z³/√w

If x = 2, z = 2, y = 12 and w = 64

Substitute;

12 = k (2)²(2)³/√64

12 = 32k/8

12 = 4k

k = 12/4

k = 3

To get y when x = 1, z = 3, and w = 4.

y = 3 (1)²(3)³/√4

y = (3*27)/2

y = 81/2

y = 40.5

Hence the value of y is 40.5

what are you trying to solve here

step-by-step explanation:

the answer is 8/21

hope this