The length of a rectangle is two times its width. Find the area if its perimeter is 7 1/3

Let x be the width

width = x

Length is twice its width

length = 2x

Perimeter = length + width + length + width

Perimeter = x + 2x + x + 2x = 6x

Given that perimeter = 7 1/3

6x = 7 1/3

x = 7 1/3 ÷ 6 = 1 2/9

So width = 1 2/9

Length = 1 2/9 x 2 = 2 4/9

Area = length x width

Area = 1 2/9 x 2 4/9

Area = 2 80/81 square cm

answer: a and b

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.