The diagonals of a rectangle have length 12 and intersect in a 40 degree angle. Find the length and width rounded to the nearest tenth.

Length is 7.7 and width is 9.2

Step-by-step explanation:

The length and width of the rectangle will be the y and x coordinate of the diagonal line at angle of 40 degrees

Length L = dsin theta

Width W = d coos theta

d is the length of the diagonal

Given

d  = 12

theta = 40°

Substitute

Length = 12sin40°

Length = 12(0.6428)

Length = 7.7135

Length ≈ 7.7

Width = 12cos 40

Width = 12(0.7660)

Width = 9.192

Width = 9.2

Hence the length is 7.7 and width is 9.2

a. 74 degrees

step-by-step explanation:

because the lines through the side and the box in the corners shows that these are congruent triangles and since they are mirrored the 37 degrees is also mirrored so the answer is 37 * 2 which is 74.

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: