The cost of staying in a hotel is given by the formula C=50d+20, where C is the cost in £ and d is the number of days a person stays. Find the cost of staying for: a) 6 days
b) 2 weeks
c) If the cost is 120 then how many days the person can stay

a) £320

b) £720

c) 2 days

Step-by-step explanation:

The question is all about inputting values and finding a result or rearranging and finding a result.

a) d = 6. C = 50(6)+20      = 320

b) d = 2x7 (7 days a week)  C = 50(2x7) + 20     = 720

c) C = 120 ... 120 = 50d+20

100 =50d      d = 100/50      = 2

muyb ajo

step-by-step explanation:

jegosu

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .