given a triangle with a perimeter of 56in. we know the first side is 3 inches less than twice the length of the second side, and the third side is 10 inches more than half the length of the second side. if the second side length is h, how long is the longest side? write an equation to solve for the variable

Side A = 25 in

Side B = 14 in

Side C = 17 in

Step-by-step explanation:

Perimeter of a triangle = 56 in

Side B = x

Side A = 2x - 3

Side C = 1/2x + 10

Perimeter of a triangle = side A + Side B + side C

56 = (2x -3) + x + (1/2x + 10)

56 = 2x - 3 + x + 1/2x + 10

56 + 3 - 10 = 2x + x + 1/2x

49 = 3 1/2x

Note: 3 1/2x = 3.5x

49 = 3.5x

x = 49/3.5

x = 14 in

Side B = x = 14 in

Side A = 2x - 3

= 2(14) - 3

= 28 - 3

= 25 in

Side C = 1/2x + 10

= 1/2(14) + 10

= 7 + 10

= 17 in

the square root of what number? if you add that, then someone will probably answer the question.

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: