What is the fewest number of consecutive primes, starting with 2, that when summed produce a number divisible by 7?

The fewest number of consecutive primes, starting with 2, that when summed produces a number divisible by 7 is 5.

To determine what is the fewest number of consecutive primes, starting with 2, that when summed produces a number divisible by 7, the following calculation must be performed:

Therefore, the fewest number of consecutive primes, starting with 2, that when summed produces a number divisible by 7 is 5.

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5

Step-by-step explanation:

The consecutive primes starting from 2 are

2, 3, 5, 7, 11

Summing gives 2 + 3 + 5 + 7 + 11 = 28

and 28 is divisible by 7

Thus the required number of primes is 5

answer: yes youre right.

step-by-step explanation:

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt