A plane is flying to Metro City. The plane started its journey 1275 miles from Metro City. Write an equation in standard form to represent the situation if the plane travels a hours at 550 mph and b hours at
590 mph.
Which equation is correctly written in standard form to represent this scenario?
0 590a - 550b = 1275
550a +590b = 1275
590a + 550b = 1275
550a - 5906 = 1275

550a + 590b = 1275

Step-by-step explanation:

We use the following relation to solve this question:

In which v is the velocity, d is the distance and t is the speed.

In this question, we find the distance, so we use:

A plane is flying to Metro City. The plane started its journey 1275 miles from Metro City.

This means that .

Write an equation in standard form to represent the situation if the plane travels a hours at 550 mph and b hours at 590 mph.

This means that .

Which equation is correctly written in standard form to represent this scenario?

1275 = 550a + 590b

550a + 590b = 1275

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

for the points! : )