Arnie is mixing red and yellow paints to make two different shades of orange. To make 1 cup of dark orange paint, he needs 7 ounces of red paint and 1 ounce of yellow paint. To make 2 cups of light orange paint, he needs 13 ounces of yellow paint and 3 ounces of red paint. Answer parts a and b.

Arnie has enough red paint

Step-by-step explanation:

step 1

Find out the number of ounces of red paint needed to make 3 cups of dark orange paint

Let

x > number of ounces of red paint

y > number of ounces of yellow paint

z > cups of dark orange

we know that

\frac{x}{z}=\frac{7}{1}\ \frac{ounces\ red\ paint}{cups\ dark\ orange}

z

x

=

1

7

cups dark orange

ounces red paint

so

For z=3 cups

substitute and solve for x

\frac{x}{3}=\frac{7}{1}

3

x

=

1

7

x=21\ ounces\ of\ red\ paintx=21 ounces of red paint

step 2

Find out the number of ounces of red paint needed to make 3 cups of light orange paint

Let

x > number of ounces of red paint

y > number of ounces of yellow paint

z > cups of light orange

we know that

\frac{x}{z}=\frac{3}{2}\ \frac{ounces\ red\ paint}{cups\ light\ orange}

z

x

=

2

3

cups light orange

ounces red paint

so

For z=3 cups

substitute and solve for x

\frac{x}{3}=\frac{3}{2}

3

x

=

2

3

x=4.5\ ounces\ of\ red\ paintx=4.5 ounces of red paint

step 3

Adds the ounces of red paint

21+4.5=25.5\ ounces\ of\ red\ paint21+4.5=25.5 ounces of red paint

25.5\ ounces < 32\ ounces25.5 ounces<32 ounces

therefore

Arnie has enough red paint

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

32

step-by-step explanation: