let x represent one number and let y represent the other number. use the given conditions to write a system of equations. solve the system and find the numbers. three times a first number decreased by a second number is 22. the first number increased by twice the second number is 12.

9514 1404 393

  (x, y) = (8, 2)

Step-by-step explanation:

The relevant equations are ...

  3x -y = 22

  x +2y = 12

__

We can eliminate y by adding twice the first equation to the second.

  2(3x -y) +(x +2y) = 2(22) +(12)

  7x = 56

  x = 8

Substituting into the first equation gives ...

  3(8) -y = 22

  y = 24 -22 = 2

The first number is 8; the second number is 2.

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)