If the vertices of quadrilateral ABCD are: A(-6,2), B(-5,5), C(1,2), and D(0,-1). Prove quadrilateral ABCD is a parallelogram.

i have no idea just need points sorry

step-by-step explanation:

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)

i don't see any steps below, sweetheart

answer: 60%

explanation:

÷

= 60%