16x^2 + 10x — 27 = -6x + 5

What are the solutions to this equation?

x=1 or x=−2

Step-by-step explanation:

16x2+10x−27=−6x+5

Step 1: Subtract -6x+5 from both sides.

16x2+10x−27−(−6x+5)=−6x+5−(−6x+5)

16x2+16x−32=0

Step 2: Factor left side of equation.

16(x−1)(x+2)=0

Step 3: Set factors equal to 0.

x−1=0 or x+2=0

x=1 or x=−2

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.