Add the following complex numbers: (2 + 3i) + (3 - 2i)

5 + i

Step-by-step explanation:

Combine real part ans combine imaginary parts

2 + 3i + 3 - 2i = 2 + 3 + 3i - 2i

                      = 5 + i

5 and 1i

Step-by-step explanation:

So you’re adding the following complex numbers: (2 + 3i) + (3 - 2i)

normally if you see a (-) in front of a number, that means it’s negative so we’re gonna think about this as -2i and positive 3.

so you’re gonna want to take the 2 regular while numbers (without the variable) and then add those together. they’re like numbers so neither of them have a variable, which means they can easily be added, but you can’t add a number like 7 to a number like 9h because there’s a variable.

Now that you’ve added the 2 and 3, you get 5 right? so now you’re gonna take the 3i and -2i, and add those together. since the number 3i is bigger than -2i, the ending number after you add those is gonna be positive, and it’s gonna be 1i.

now i’m not sure if you’re supposed to make an equation out of this but you’re answer will be 5 and 1i or 5 + 1i

also if you don’t want to put 1i, 1i is the same as just “i”. so you can put 5 + i :)

hope this helped!!

answer: hi

step-by-step explanation:

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i