In AGHI, GI is extended through point I to point J, mZGHI = (2x - 3)º, mZIGH = (2x + 15)°, and m_HIJ = (7x – 18)'. Find mZGHI.

m<GHI = 17°

Step-by-step explanation:

m<GHI = (2x - 3)°

m<IGH = (2x + 15)°

m<HIJ = (7x - 18)°

<HIJ is an exterior angle of ∆GHI

<GHI and <HIJ are both interior angles of ∆GHI that are opposite to the exterior angle.

Therefore, based on the exterior angle theorem of a triangle, we would have the following equation:

m<GHI + m<IGH = m<HIJ

(2x - 3)° + (2x + 15)° = (7x - 18)° (substitution)

Solve for x

2x - 3 + 2x + 15 = 7x - 18

Add like terms

4x + 12 = 7x - 18

4x - 7x = -12 - 18

-3x = -30

Divide both sides by -3

x = 10

✔️m<GHI = (2x - 3)°

Plug in the value of x

m<GHI = 2(10) - 3 = 20 - 3

m<GHI = 17°

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: