A boy and his friend wish to calculate the height of a flagpole. One boy holds a yardstick vertically at a point 40 feet from the base of a flagpole, as shown. The other boy backs away from the pole to a point where he sees the top of the flagpole over the top of the yardstick. If his position is 1 foot 9 inches from the yardstick and his eye level is 2 feet above the ground. Find the height of the flagpole in inches. Round to the nearest whole inch.

One boy holds a yardstick vertically at a point 40 feet from the base of the flagpole. The other boy backs away from the pole to a point where he sights the top of the pole over the top of the yardstick. If his position is 1 ft 9 in from the yardstick and his eye level is 2 ft above the ground, find the height of the flagpole.

Hello,

Did you draw a diagram?

Flag pole

The second boy's eye, the top of the yard stick and the top of the flagpole form a straight line. I extended this line to meet the ground at E and called the distance the second boy to the ground |DE| = x feet.

The triangles GCE and FDE are similar and hence

|CE|/|GC| = |DE|/|FD|

(1' 9" + x')/3' = x'/2'

But 1' 9" = 1.75' and hence you can solve the above equation for x.

Now use the fact that triangles ABE and FDE are similar to find h.

Chase-

Step-by-step explanation:

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.