A secant and a tangent meet at a 90° angle outside the circle. What must be the difference between the measures of the intercepted arcs?
O 45°
O 90°
O 180°
O 270°

i can

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group