5. Carlos and Mike are selling cheesecakes for a school fundraiser. Customers can buy pecan cheesecakes and apple cheesecakes. Carlos sold 1 pecan cheesecake and 4 apple cheesecakes for a total
of $44. Mike sold 14 pecan cheesecakes and 14 apple cheesecakes for a total of $238. Find the cost
each of one pecan cheesecake and one apple cheesecake.
a. Define variables:
b. System:
c. Solve the systems (optional):

One pecan costs $8. One apple costs $9.

Step-by-step explanation:

p and a are number of number of pecan and apple sold, respectively.

"1 pecan cheesecake and 4 apple cheesecakes for $44"

p + 4a = 44

"14 pecan cheesecakes and 14 apple cheesecakes for $238"

14p + 14a = 238

You have a system of two equations in two unknowns:

p + 4a = 44

14p + 14a = 238

Eliminate the p terms: Multiply the first equation by -14, then add the product to the second equation.

-14p  - 56a = -616

 14p + 14a = 238

  -42a = -378

a = (-378)/(-42) = 9

p = 44-4a = 8

One pecan costs $8. One apple costs $9.

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.