How many liters of a 10% solution should be mixed with 60 liters of a 25% solution to get a 15% solution?

120 liters of the 10% solution should be mixed with 60 liters of a 25% solution to  get a 15% solution.

Step-by-step explanation:

Let 'x' be the quantity of 10% solution

Given that we need determine many liters of a 10% solution should be mixed with 60 liters of a 25% solution to  get a 15% solution.

As

10% of x = 0.1x

60 liters of a 25%  = 60 × 0.25

Thus,

The equation becomes

Multiply both sides by 100  

Subtract 1500 from both sides

Simplify

Subtract 15x from both sides

Simplify

Divide both sides by -5

Simplify

Therefore,

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15