-x+y+z=1, x-y+z=2, x+y-z=1

(3/2, 1, 3/2)

Step-by-step explanation:

Given the simultaneous equation

-x+y+z=1... 1

x-y+z=2 ... 2

x+y-z=1 3

Add equation 1 and 2;

-x+x + y - y + z + z = 1+2

0 + 0 + 2z = 3

2z = 3

z = 3/2

Add equation 2 and 3

x+x = 2 + 1

2x = 3

x = 3/2

Substitute x = 3/2 and z = 3/2 into 3

From 3;

x+y-z = 1

3/2 + y - 3/2 = 1

y + 0 = 1

y = 1

Hence the solution (x, y, z) is (3/2, 1, 3/2)

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2