For a right circular cylinder, if the radius is tripled and the height is shrunk down to half its size, then what is the surface area if the original radius is 7 inches and the original height is 17 inches? Round your answer to the nearest
hundredth.
A. 3,289.43 in.2
B. 3,298.43 in.2
C. 3,892.43 in.2
D. 3,982.43 in.2

Please only answer if you know. Thank you!

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)

y=20x

: )

hope this

365

step-by-step explanation: