3) When Jackie took her children to the movie theater, she bought one box of candy and three small drinks for $14.75. When Alex went to the same theater and bought two boxes of candy and five small drinks, he paid
$26.
a) Set up a system of equations to model this situation. Be sure to define the variables that you use.
b) Determine, algebraically, the cost for one box of candy and one small drink

c + 3d = 14.75

2c + 5d = 26

A box of candy is $4.25 and a drink is $3.50

Step-by-step explanation:

Let c represent the cost of a box of candy and let d represent the cost of a drink

c + 3d = 14.75

2c + 5d = 26

Solve by elimination by multiplying the top equation by -2

-2c - 6d = -29.5

2c + 5d = 26

Add them together

-d = -3.5

d = 3.5

Plug in 3.5 as d into one of the equations to solve for c

c + 3d = 14.75

c + 3(3.5) = 14.75

c + 10.5 = 14.75

c = 4.25

So, a box of candy is $4.25 and a drink is $3.50