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Mathematics, 04.02.2021 04:00 amoore51

Sam completed the square for the quadratic equation y=12x2βˆ’2x+3 in order to determine the minimum value of the equation, as shown. Step 1: y=12(x2βˆ’1x+32) Step 2: y=12(x2βˆ’x+14βˆ’14+32) Step 3: y=12((xβˆ’12)2βˆ’14+32) Step 4: y=12((xβˆ’12)2+54) Step 5: y=12(xβˆ’12)2+58 What mistake, if any, did Sam make?

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