Jack plotted the graph below to show the relationship between the temperature of his city and the number of ice cream cones he sold daily: Main title on graph is Ice Cream Cone Sale. Graph shows 0 to 30 on x axis at increments of 5 and 0 to 60 on y axis at increments of 10. The label on the x axis is Temperature in degree C, and the label on the y axis is Number of Ice Cream Cones Sold. Dots are made at the ordered pairs 0, 5 and 5, 15 and 7.5, 15 and 10, 24 and 10, 28 and 12, 32 and 12.5, 25 and 12.5, 30 and 15, 35 and 15, 40 and 17.5, 35 and 20, 45 and 22.5, 36 and 23, 46 and 25, 55 and 27.5, 60.
Part A: In your own words, describe the relationship between the temperature of the city and the number of ice cream cones sold.

Part B: Describe how you can make the line of best fit. Write the approximate slope and y-intercept of the line of best fit. Show your work, including the points that you use to calculate slope and y-intercept.

e) none of the above because the measure of angle cba is 101°

the ratio of balloons to tables is 5: 2 and the constant variation is 5.

the equation is y=5x

i have no idea just need points sorry

step-by-step explanation:

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.