A)select the equation that has a y-intercept value of 3 A:y=(x+1)(x-3)
B: y=x^2-9
C:y=3x(x-3)
D:y=(x+1)(x+3
b) Select the equation with roots 0 and 3
A:(x+1)(x-3)=0
B:x^2-9=0
C:3x(x-3)=0
D:(x+1)(x+3)=0

the expected value of the random variable : 0, 1 and 2

step-by-step explanation:

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p