Solve the right triangle ABC, with C=90 degrees. A=31.3 degrees, c= 18.6ft

B=
a=
b=
simply your answer, type a decimal or integer, round to the nearest tenth as needed
this homework is due in 2 days

B = 58.7°

b = 15.9 ft

a = 9.7 ft

Step-by-step explanation:

We are given;

C = 90°

A = 31.3°

c = 18.6 ft

Since sun of angles in a triangle is 180°, thus; B = 180 - (90 + 31.3)

B = 58.7°

From law of sines, we can find b.

Thus; b/sin B = c/sin C

b/sin 58.7 = 18.6/sin 90

b/0.8545 = 18.6/1

b = 18.6 × 0.8545

b = 15.8937 ft

To the nearest tenth gives;

b = 15.9 ft

Similarly;

a/sin A = c/Sin C

a/sin 31.3 = 18.6/sin 90

a/0.5195 = 18.6

a = 18.6 × 0.5195

a = 9.6627

To the nearest tenth gives;

a = 9.7 ft

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )