Calculate the total number of measles cases in the US in 1960. According to the census the population of the United States in 1960 was
179,323,175. Use the rate of cases per 100,000 people from the table
(remember the word "per" is the line in the rate). Fill in the proportion below
with the correct numbers:
का
179.323.175
100.000
237.1
Now use the steps for solving the proportion to find out how many total cases
of measles there were in the United States in 1960 (round to the ones place).
425.175
X-
total cases of measles in the United States in 1960

sup

step-by-step explanation:

addition

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;