The area of a circle is modeled by the equation A = πr^2. Rewrite the equation in terms of the circles radius r. In your final answer, include all of your calculations. (brainliest to best answer)

First off, the area of a circle should be pi times r squared, not r times pi squared. I will do my math using this correction.

If A = (pi)r^2 then first we can devide both sides by pi, leaving

A/pi = r^2

 To solve for r, we need to take the square root of both sides, leaving

sqrt(A/pi) = r

or

r = sqrt(A/pi)

Step-by-step explanation:

this would be your answer

r = √(A/π)

Step-by-step explanation:

A = πr²

A/π = r²

±√(A/π) = r

But the only thing is that you can't have a negative radius, so you just have to  rewrite  the answer as positive.

√(A/π) = r

answer: x=60

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.