5x + 9y, when x=8, y=11 a 3 –c + b, when a=3, b=6, c=8
4(g –h) +10,when g=12, h=7
4(g –h) +10,when g=12, h=7
k 3 –4j +12, when k=8, j=2
help pl

Please check the explanation.

Step-by-step explanation:

Part 1)

5x + 9y, when x=8, y=11

substituting x=8, y=11 in 5x + 9

5x + 9y = 5(8) + 9(11)

            = 40 + 99

            = 139

Part 2)

a³ –c + b, when a=3, b=6, c=8

substituting a=3, b=6, c=8 in a³ –c + b

a³ –c + b = (3)³ - 8 + 6

               = 27 - 2

               = 25

Part 3)

4(g –h) +10, when g=12, h=7

substituting g=12, h=7 in 4(g –h) +10

4(g –h) +10 = 4(12 - 7) + 10

                  = 4(5) + 10

                  = 20 + 10

                  = 30

Part 4)

k³ –4j +12, when k=8, j=2

substituting k=8, j=2 in k³ –4j +12

k³ –4j +12 = (8)³ - 4(2) + 12

                 = 512 - 8 + 12

                 = 516

Summary: