Solve the system 2y+8x+58 and y-5x=11

x=2, y=21

Step-by-step explanation:

there are two methods: substiution and elimation. I will be doing subtistution in this soultion:

first isolate y in either equation, it would be easier to do it in the second one.

y= 11+5x

Then, subtitute that into the first equation

2(11+5x)+8x=58 (it says 2y+8x+58 but I assume you mean 2y+8x=58?)

22+10x+8x=58

18x = 36

x=2

substitute that back into y = 11+5x, to get y=11+10 = 21

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1