50 Points and BRAINLIEST A rectangle is placed around a semicircle as shown below. the width of the rectangle is 9ft . find the area of the shaded region. use the value 3.14 for π , and do not round your answer. be sure to include the correct unit in your answer.

15.48 i think

Step-by-step explanation:

15.48 ft^2

Step-by-step explanation:

As the figure is missing, I will do the most logical assumptions and explain the way to solve the problem.

1) radius of the semicircle = width of the rectangle = 6ft

2) length of the rectangle = 2*radius of the semicircle = 12 ft

3) Area of the shaded region = area of the rectangle - area of the semicircle

area of the rectangle = width * length = 6 ft * 12 ft = 72 ft^2

area of the semicircle = [1/2]*π*(r^2) = [1/2]*3.14*(6ft)^2 = 56.52 ft^2

area of the shaded region = 72 ft^2 - 56.52 ft^2 = 15.48ft^2

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

i hope this is what you were looking for.

see attached graph