If line q has a slope of -3/8, what is the slope of any line perpendicular to to q?

The slope of line perpendicular to line q is 8/3.

Step-by-step explanation:

Given that:

Slope of a line q is -3/8

Slope is the steepness of any line.

Let,

x be the slope of line perpendicular to line q.

The product of slopes of two perpendicular lines is equal to -1.

Multiplying both sides -8/3

x = 8/3

Hence,

The slope of line perpendicular to line q is 8/3.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.