Tickets for a concert cost $4.00 for a balcony seat and $7.50 for an orchestra seat. If ticket sales totaled $1,585 for 300 tickets sold, how many more tickets for balcony seats were sold than tickets for orchestra seats? - thanks

there were 80 more tickets sold for balcony seats than for orchestra seats

Step-by-step explanation:

Step 1

Let number of tIcket for balcony be represented as x

and

Number of tickets for orchestra seat be represented as y such that the total number pf tickets sol;d would be

X+ Y = 300--- equation 1

And the cost for $4.00 for a balcony seat and $7.50 for an orchestra seat totalling ticket sales of $1,585 be represented as

4x + 7.50y = 1585 equation 2

Step 2

X+ Y = 300--- equation 1

4x + 7.50y = 1585 equation 2

Multiplying equation 1 by 4 and subtracting from equation2

4x + 7.50y = 1585

-4x+4y= 1200

3.50y =385

y =385/3.50

y=110

To find x, when y=110

X+ Y = 300--- equation 1

x+110=300

x= 300-110= 190 tickets

balcony seats  tickets = 190

orchestra seats tickets = 110

Therefore, there were 80 more tickets sold for balcony seats than for orchestra seats

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!

lol 2

step-by-step explanation: