PLEASE ANSWER THIS QUESTION RIGHT. The height of Ryan's rocket is represented by the table of values h(t) below, where t represents time in seconds. Part A:What is the maximum height of the rocket reached?
A.146 feet
B.128 feet
C.100 feet
D.68 feet

Part B: how long did it take for the rocket to reach the ground?
A.1.5 seconds
B.2 seconds
C.4.5 seconds
D.1 second

maximum height reached = 35 feet

and  

Step-by-step explanation:

writing linear motion equations

where s is the total displacement, u the initial velocity, t the time travelled, and a is the acceleration.

given u = 48 ft/s, and a = acceleration due to gravity g = -9.8

1 m = 3.28 feet therefore g becomes -9.8×3.28

here negative sigh comes as acceleration due to gravity is in opposite direction of initial velocity.

therefore f(t) becomes  

to find max height we should find differentiation of f(t) and equate it to 0

therefore we get 48 = 32.144t

t = 1.49 s

therefore max height f(1.49) = 71.67-36.67 = 35 feet

Step-by-step explanation: