Prove (n + 6)² – (n + 2)² is always a multiple of 8

Step-by-step explanation:

(n+6)^2-(n+2)^2=(n+6-n-2)*(n+6+n+2)=4*2*(n+4)=8*(n+4) so it is always a multiple of 8

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

answer: (1,3) and (-2,0) i think.