Solve the inequality x^2+ 3x-4 ≥ 0

Finding the roots of the given equation as shown below:

x

2

+3x−4>0

x

2

+4x−x−4>0

x(x+4)−1(x+4)>0

(x+4)(x−1)>0

Case-1:- Case-2:-

x−1>0 and x+4>0 x−1<0 and x+4<0

x>1 and x>−4 x<1 and x<−4

from above two we get from above two we get

x>1 …(1) x<−4 …(2)

From (1) and (2)

x lies between (−∞,−4)∪(1,+∞).

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: