Write an inequality to describe the possible values of x.

x = 9.934

Step-by-step explanation:

Law of sines: a/sin A = b/sin B = c/ sin C

10/sin (5x-10)° = DE/sin ∠DCE    (in ΔDCE)

12/sin 50° = AB/sin ∠ACB

AB=DE     ∠DCE = ∠ACB    DE/sin ∠DCE = AB/sin ∠ACB

10/sin (5x-10)° = 12/sin 50°

sin (5x-10)° = 10/12 * sin 50° = 5/6 * sin 50° = 5/6*0.766 = 0.638

5x - 10 = 39.67

5x = 49.67

x = 9.934

X has a value, if that's not correct... just report it.

answer: the answer is 40.82

step-by-step explanation: 3.14 x 13(or half of 26) to the power of 2

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2