Imagine the center of the ferris wheel is located at (0, 0) on a coordinate grid, and the radius lies on the x-axis. Write an equation of a circle for your ferris wheel, and sketch an image of what your ferris wheel would look like on the grid. Now graph a circle that is similar to the Ferris Wheel. Discuss the transformations needed to show that both circles on your graph are similar.

(X - H)^2 + (Y -  K)^2 =  R^2  (X - 0)^2 + (Y - 0)^2 = 60^2  X^2 + Y^2 = 3,600

Step-by-step explanation:

I got an A

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15