An object is launched directly in the air at a speed of 72 feet per second from a platform located 12 feet above the ground. The position of the object can be modeled using the function f(t)=−16t2+72t+12, where t is the time in seconds and f(t) is the height, in feet, of the object. What is the maximum height, in feet, that the object will reach?

93 feet

Step-by-step explanation:

The highest point the object will be the vertex of the given function. Because the derivative of the function at the vertex is zero, we can set up the equation f'(t)=0. After substituting, we get t=2.25 as the x coordinate. when we plug this vaule we get 93.

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step-by-step explanation:

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step-by-step explanation:

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