14. In the following figure, M is the midpoint of (FA) and (MA) and (MB) are the tangents issued
from M to the circle(C).
F
M
B
(C)
question: Show that ABF is a right triangle.

angle OAM and OBM are right angles because tangents form right angles with radii.

AO=BO and MA=MB

Quadrilateral MAOB =360 degrees

so angles AOB and AMB=90 degrees each

angle MBF=90 degrees

M is the midpoint of FA so MA=MF

MB=MF

Triangle MBF is a right triangle because angle BMF is 90 degrees and  MB=MF

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.