Ali hops on his 3 wheeler and heads off at 12 mph. Two hours later, Fatimah chases after him on a moped at 18 mph. How far will Ali get before Fatimah overtakes him? Write the system equations.

72 miles.

Step-by-step explanation:

We know the relationship:

Distance = speed*time.

Then we can write the equation for distance as a function of time for Ali as:

A(t) = 12mph*t

where t is time in hours.

Fatimah's equation will be:

F(t) = 18mph*(t - 2h)

where the -2h appears because she starts two hours after Ali.

Fatimah will overtake Ali when F(t) = A(t) (their positions are the same)

Then we need to solve:

12mph*t = 18mph*(t - 2h)

12mph*t = 18mph*t - 18mph*2h

12mph*t = 18mph*t - 36 mi

36 mi = (18mph - 12mph)*t

36mi = 6mph*t

36mi/6mph = t

6h = t

So Ali travels for 6 hours before he gets overtaken, then the total distance that Ali travels is:

A(6h) = 12mph*6h = 72 mi

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.