The formula for the area of a triangle is Area = 1 2 × base × height. How much greater is the area of Triangle B than the area of Triangle A? A. 4 cm2 B. 5.9 cm2 C. 11.8 cm2 D. 23.6 cm2

Hello your question is not well written hence I will given a general answer with some assumptions

lets assume ; Triangle A : height = 4 , base = 2

                      Triangle B : height = 6 , base = 4

Step-by-step explanation:

Given data :

Triangle A : height = 4 , base = 2

Triangle B : height = 6 , base = 4

Area of triangle = 1/2 bh

Area of triangle of A = 1/2 * 2 * 4 = 8/2 = 4 cm^2

Area of triangle of B = 1/2 * 6 * 4 = 24/2 = 12 cm^2

Hence the area of triangle B is greater than triangle A by

= 12 - 4 = 8cm^2 ( apply the same principle to the complete question and you will get your answer )

what is all that apply?

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.